(b)x^2+(b+3)x^2=15x^2

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Solution for (b)x^2+(b+3)x^2=15x^2 equation:


Simplifying
(b) * x2 + (b + 3) * x2 = 15x2

Multiply b * x2
bx2 + (b + 3) * x2 = 15x2

Reorder the terms:
bx2 + (3 + b) * x2 = 15x2

Reorder the terms for easier multiplication:
bx2 + x2(3 + b) = 15x2
bx2 + (3 * x2 + b * x2) = 15x2

Reorder the terms:
bx2 + (bx2 + 3x2) = 15x2
bx2 + (bx2 + 3x2) = 15x2

Combine like terms: bx2 + bx2 = 2bx2
2bx2 + 3x2 = 15x2

Solving
2bx2 + 3x2 = 15x2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3x2' to each side of the equation.
2bx2 + 3x2 + -3x2 = 15x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
2bx2 + 0 = 15x2 + -3x2
2bx2 = 15x2 + -3x2

Combine like terms: 15x2 + -3x2 = 12x2
2bx2 = 12x2

Divide each side by '2x2'.
b = 6

Simplifying
b = 6

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